# Line slope calculator 10x-7y=30

**Straight line given by points A[3; 0] and B[10; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.4286x-4.2857

**Canonical form of the line equation:**10x-7y-30 = 0

**Parametric form of the line equation:**

x = 7t+3

y = 10t ; t ∈ R

**Slope:**m = 1.4286

**Slope angle of line: φ =**55°29″ = 0.9601 rad

**X intercept:**x

_{0}= 3

**Y intercept:**y

_{0}= q = -4.2857

**Distance line from the origin:**d

_{0}= 2.4577

**The length of the segment AB: |AB| =**12.2066

**Vector: AB =**(7; 10)

**Normal vector: n =**(10; -7)

**Midpoint of the segment AB: M =**[6.5; 5]

**Perpendicular Bisector equation:**7x+10y-95.5 = 0

**Vector OA = (3; 0) ; |OA| = 3**

**Vector OB = (10; 10) ; |OB| = 14.1421**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 45° = 0.7854 rad**